ElectroMagnetic InductionHard

Question

The circuit shown in figure is allowed to reach steady state and then a soft iron core is inserted in the coil such that its coefficient of self inductance changes from L to nL. The steady current in the circuit after complete insertion is
         

Options

A.
B.
C.
D.Zero

Solution

In steady state, inductor will behave as shortcircuit so i =

Create a free account to view solution

View Solution Free
Topic: ElectroMagnetic Induction·Practice all ElectroMagnetic Induction questions

More ElectroMagnetic Induction Questions