Laws of MotionMedium
Question
The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively:
Options
A.$20\text{ }m{\text{ }s}^{- 2}$; $\tan^{- 1}(4/3)$ with 8 N force
B.$2\text{ }m{\text{ }s}^{- 2}$; $\tan^{- 1}(3/4)$ with 6 N force
C.$2\text{ }m{\text{ }s}^{- 2}$; $\tan^{- 1}(4/3)$ with 8 N force
D.$2\text{ }m{\text{ }s}^{- 2}$; $\tan^{- 1}(3/4)$ with 8 N force
Solution
Sol. [Key Concept: Wave parameters from y(x,t)]
$$\begin{matrix} & F_{\text{net}\text{~}} = \sqrt{6^{2} + 8^{2}} \\ & a = \frac{F_{\text{net}\text{~}}}{m} = \frac{10}{5} = 2\text{ }m/s^{2} \\ & tan\theta = \frac{6}{8} \\ & \theta = \tan^{- 1}\left( \frac{3}{4} \right)\text{~}\text{from}\text{~}8\text{ }N \end{matrix}$$
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