Laws of MotionHard
Question
A system is shown in the figure. A man standing on the block is pulling the rope. Velocity of the point of string in contact with the hand of the man is 2 m/s downwards. The velocity of the block will be: [ assume that the block does not rotate]
Options
A.3 m/s
B.2 m/s
C.1/2 m/s
D.1 m/s
Solution
(B)
l1 + l2 + l3 + l4 = C
= 0
−v − v + 0 + v + 2 = 0 v = 2m/s
l1 + l2 + l3 + l4 = C
= 0−v − v + 0 + v + 2 = 0 v = 2m/s
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A block is first placed on its long side and then on its short side on the same inclined plane (see figure ) . The block...A particle is moving with a constant speed along a straight line path. A force is not required to :...Two blocks, each having mass M, rest on frictionless surfaces as shown in the figure. If the pulleys are light and frict...A 60 kg man stands on a spring scale of a lift. At some instant he finds the scale reading has changed from 60 kg to 50 ...The force exerted by the person on the floor of the elevator is more than the weight of the person if the elevator is :-...