Laws of MotionHard
Question
A system is shown in the figure. A man standing on the block is pulling the rope. Velocity of the point of string in contact with the hand of the man is 2 m/s downwards. The velocity of the block will be: [ assume that the block does not rotate]
Options
A.3 m/s
B.2 m/s
C.1/2 m/s
D.1 m/s
Solution
(B)
l1 + l2 + l3 + l4 = C
= 0
−v − v + 0 + v + 2 = 0 v = 2m/s
l1 + l2 + l3 + l4 = C
= 0−v − v + 0 + v + 2 = 0 v = 2m/s
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