General Organic ChemistryMedium
Question
The correct order of decreasing acidity of the following aliphatic acids is
Options
A.$\left( {CH}_{3} \right)_{3}CCOOH > \left( {CH}_{3} \right)_{2}CHCOOH > {CH}_{3}COOH > HCOOH$
B.${CH}_{3}COOH > \left( {CH}_{3} \right)_{2}CHCOOH > \left( {CH}_{3} \right)_{3}CCOOH > HCOOH$
C.$HCOOH > {CH}_{3}COOH > \left( {CH}_{3} \right)_{2}CHCOOH > \left( {CH}_{3} \right)_{3}CCOOH$
D.$HCOOH > \left( {CH}_{3} \right)_{3}CCOOH > \left( {CH}_{3} \right)_{2}CHCOOH > {CH}_{3}COOH$
Solution
Sol. [Key Concept: Order of decreasing acidity of aliphatic carboxylic acids]
Electron donating group decreases the acidity of carboxylic acids.
So correct order is $HCOOH > {CH}_{3}COOH > \left( {CH}_{3} \right)_{2}CHCOOH > \left( {CH}_{3} \right)_{3}CCOOH$
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