d and f-Block ElementsMedium

Question

The calculated 'spin-only' magnetic moment ${Ti}^{2 +}\left( 3{\text{ }d}^{2} \right)$ is :

Options

A.5.92 BM
B.3.87 BM
C.2.84 BM
D.4.90 BM

Solution

Sol. [Key Concept: Spin-only magnetic moment μ = √n(n+2) BM]

Spin only magnetic moment $\mu = \sqrt{n(n + 2)}$ B.M

$n =$ Number of unpaired $e^{-}(s)$

Electronic configuration of ${Ti}^{2 +} \Rightarrow \lbrack Ar\rbrack 4s^{0}3d^{2}$

$$\begin{matrix} \mu & \ = \sqrt{2 \times 4} \\ & \ = 2.84BM \end{matrix}$$

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