ThermodynamicsMedium
Question
At a certain temperature, $T(K)$, during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then change in internal energy of the system is:
Options
A.400 J
B.300 J
C.700 J
D.500 J
Solution
Sol. [Key Concept: First law of thermodynamics: ΔU = q + w]
From first law of thermodynamics
$$\begin{matrix} \Delta U & \ = q + w \\ q & \ = + 500\text{ }J \\ w & \ = - 200\text{ }J \\ \Delta U & \ = 500 - 200 \\ & \ = 300\text{ }J \end{matrix}$$
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