Redox and Equivalent ConceptMedium

Question

Although +3 oxidation state is most common in lanthanoids, cerium still shows +4 oxidation state because:

Options

A.After losing one more electron, it acquires $4f^{14}$ electronic configuration.
B.Its nearest inert gas is Radon.
C.Its atomic number is 61.
D.After losing one more electron, it acquires $4f^{0}$ electronic configuration.

Solution

Sol. [Key Concept: Ce⁴⁺ stability — attaining the 4f⁰ configuration] Although +3 oxidation state is most common in lanthanoids, cerium still shows +4 oxidation state because after losing one more electron it acquires $4f^{0}$ electronic configuration.

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