Chemical BondingMedium
Question
Match List I with List II:
| List I | List II | ||
|---|---|---|---|
| A. | $$C_{2}H_{4}$$ | I. | $3\sigma$ bonds, $2\pi$ bonds |
| B. | $$C_{2}H_{2}$$ | II. | $3\sigma$ bonds, one lone pair |
| C. | $${CH}_{4}$$ | III. | $4\sigma$ bonds |
| D. | $${NH}_{3}$$ | IV. | $5\sigma$ bonds, $1\pi$ bond |
Choose the correct Ans. from the options given below:
Options
A.A-III, B-IV, C-II, D-I
B.A-IV, B-I, C-III, D-II
C.A-I, B-II, C-IV, D-III
D.A-II, B-III, C-I, D-IV
Solution
Sol. [Key Concept: Matching polymers/biomolecules with type]
Number of $\sigma$ bonds $= 5$
Number of $\pi$ bond $= 1$
$$C_{2}H_{2} \Rightarrow H - C \equiv C - H $$Number of $\sigma$-bonds $= 3$
Number of $\pi$-bonds $= 2$
Number of $\sigma$-bonds $= 4$
Number of $\sigma$-bonds $= 3$
Number of lone pair = one
A-IV, B-I, C-III, D-II
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