Chemical Kinetics and Nuclear ChemistryMedium
Question
Match List I with List II:
| List-I (Order of reaction) | List-II (Unit of rate constant) | ||
|---|---|---|---|
| A. | Zero order | I. | $${mol}^{- 1}\text{ }L{\text{ }s}^{- 1}$$ |
| B. | First order | II. | $${mol}^{- 2}{\text{ }L}^{2}{\text{ }s}^{- 1}$$ |
| C. | Second order | III. | $$s^{- 1}$$ |
| D. | Third order | IV. | $$molL^{- 1}{\text{ }s}^{- 1}$$ |
Choose the correct Ans. from the options given below :
Options
A.A-IV, B-II, C-I, D-III
B.A-IV, B-III, C-I, D-II
C.A-IV, B-III, C-II, D-I
D.A-I, B-II, C-III, D-IV
Solution
Sol. [Key Concept: Matching coordination/structure concepts]
Unit for rate constant of $n^{\text{th}\text{~}}$ order reaction $= \left( \frac{mol}{L} \right)^{1 - n}s^{- 1}$
For zero order reaction $\Rightarrow n = 0$; unit $\Rightarrow molL^{- 1}{\text{ }s}^{- 1}$
For first order reaction $\Rightarrow n = 1$; unit $\Rightarrow s^{- 1}$
For second order reaction $\Rightarrow n = 2$; unit $\Rightarrow {mol}^{- 1}\text{ }L{\text{ }s}^{- 1}$
For third order reaction $\Rightarrow n = 2$; unit $\Rightarrow {mol}^{- 2}{\text{ }L}^{2}{\text{ }s}^{- 1}$
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