Question
An urn contains 20 white marbles, 30 blue marbles and 50 red marbles. Ten marbles are selected, one at a time, with replacement. Then the probability that at least one colour will be missing from the 10 selected marbles is
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Solution
Sol. [Key Concept: Urn 20W+30B+50…: probability by counting.]
$A \rightarrow$ event that white balls are not among the 10 selected marbles.
B → event that blue balls are not among the 10 selected marbles.
$C \rightarrow$ event that red balls are not among the 10 selected marbles.
$$\begin{matrix} P(A \cup B \cup C) & \ = \left( \frac{80}{100} \right)^{10} + \left( \frac{70}{100} \right)^{10} + \left( \frac{50}{100} \right)^{10} - \left( \frac{50}{100} \right)^{10} - \left( \frac{30}{100} \right)^{10} - \left( \frac{20}{100} \right)^{10} \\ & \ = \frac{8^{10} + 7^{10} - 3^{10} - 2^{10}}{10^{10}} \end{matrix}$$
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