Progression (Sequence and Series)HardBloom L3
Question
Let $S = 2016^{2} + 2015^{2} + 2014^{2} - 2013^{2} - 2012^{2} - 2011^{2} + 2010^{2} + 2009^{2} + 2008^{2} - 2007^{2} - 2006^{2} - 2005^{2} + \ldots. + 6^{2} + 5^{2} + 4^{2} - 3^{2} - 2^{2} - 1^{2}$, then S is divisible by
Options
A.8
B.27
C.112
D.2017
Solution
Sol. [Key Concept: Factor the sum $S$ to test divisibility.]
$$S = 3(1 + 2 + 3 + 4 + \ldots + 2016) = 2^{4} \times 3^{3} \times 7 \times 2017$$
$$\left\lbrack \because 6^{2} + 5^{2} + 4^{2} - 3^{2} - 2^{2} - 1^{2} = 3\lbrack(6 + 3) + (5 + 2) + (4 + 1)\rbrack \right.\ $$
$$= 3(1 + 2 + 3 + 4 + 5 + 6)\rbrack$$
✔ (a) $S{= 2}^{4} \cdot 3^{3} \cdot 7 \cdot 2017$, divisible by 8
✔ (b) divisible by 27
✔ (c) divisible by 112
✔ (d) divisible by 2017
Create a free account to view solution
View Solution FreeMore Progression (Sequence and Series) Questions
If 4th term of an AP is 64 and its 54th term is − 61, then its common difference is −...Fifth term of a GP is 2, then the product of its 9 terms is...The sum of first 20 terms of the sequence 0.7,0.77, 0.777, ......, is :...The sum of first 9 terms of the series + .... is....Let $a_{1},a_{2},a_{3},\ldots.,a_{n}$ are in A.P., then...