ElectrostaticsMedium
Question
Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. Charge on each sphere is $q$ and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact with sphere $A$ first and then with $B$ and finally removed from both. New force of repulsion between spheres $A$ and $B$ (Radii of $A$ and $B$ are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as:
Options
A.$\frac{3F}{5}$
B.$\frac{2F}{3}$
C.$\frac{F}{2}$
D.$\frac{3F}{8}$
Solution
$$F = \frac{Kqq}{r^{2}}$$
$$\begin{matrix} F^{'} & \ = \frac{\frac{Kq}{2}\frac{3q}{4}}{r^{2}} \\ F^{'} & \ = \frac{3F}{8} \end{matrix}$$
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