ElectrostaticsHard
Question
Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge of the electron)
Options
A.

B.

C.

D.

Solution
According to Coulamb′s law the force of repulsion between the two positive ions in each of the charge q, separated by a distance d is given by


q2 = 4πε0Fd2
......(i)
Since, q = ne
where,
n = number of electrons missing from ion
e = magnitude of charge on electron
∴ n =
[Using (i)]



q2 = 4πε0Fd2
......(i)Since, q = ne
where,
n = number of electrons missing from ion
e = magnitude of charge on electron
∴ n =

[Using (i)]
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
The electric potential outside a uniformily charged sphere at a distance r is (a = radius of sphere) -...In millikan′s oil drop experiment, which of the following charges can be present on the oil drops -...Two points P and Q are maintained at the potentials of 10V and - 4V respectively. The work done in moving 100 electrons ...In figure a point charge +Q1 is at the center of an imaginary spherical surface and another point charge +Q2 is outside ...At distance of 5cm and 10cm outwards from the surface of a uniformly charged solid sphere, the potentials are 100V and 7...