$AB$ is a part of an electrical circuit (see figure). The potential difference " $V_{A} - V_{B}$ ",

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$AB$ is a part of an electrical circuit (see figure). The potential difference " $V_{A} - V_{B}$ ", at the instant when current $i = 2	ext{ }A$ and is increasing at a rate of $1amp/$ second is:

Accepted Answer

$$\begin{matrix} & 	ext{~}	ext{Given,}	ext{~}I = 2	ext{ }A	ext{~}	ext{and}	ext{~}\frac{di}{dt} = + 1	ext{ }A/s \ & V_{A} - L\frac{di}{dt} - 5 - i 	imes 2 = V_{B} \ & \ \Rightarrow V_{A} - 1 	imes 1 - 5 - 2 	imes 2 = V_{B} \ & \ \Rightarrow V_{A} - V_{B} = 10volt \end{matrix}$$

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