CircleHardBloom L3
Question
The locus of the centers of the circles which cut the circles $x^{2} + y^{2} + 4x - 6y + 9 = 0$ and $x^{2} + y^{2} - 5x + 4y - 2 = 0$ orthogonally is:
Options
A.$9x + 10y - 7 = 0$
B.$x - y + 2 = 0$
C.$9x - 10y + 11 = 0$
D.$9x + 10y + 7 = 0$
Solution
[Key Concept: Centres of circles cutting given circles orthogonally lie on a line (the radical axis of orthogonality).]
Locus of centers will be the radical axis of two given circles given by
$$9x - 10y + 11 = 0$$
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