CircleHard
Question
AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB. The tangent at B meets the line AC produced at E then AE is equal to -
Options
A.AB
B.√2 AB
C.2√2 AB
D.2AB
Solution
∠CAB = 60o
In ᐃABE
cos 60o =
⇒ AE = 2AB
Solving above equation and get value of r.
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