CircleHardBloom L3

Question

The centre of the smallest circle touching the circles $x^{2} + y^{2} - 2y - 3 = 0$ and $x^{2} + y^{2} - 8x - 18y + 93 = 0$ is:

Options

A.$(3,2)$
B.$(4,4)$
C.$(2,7)$
D.$(2,5)$

Solution

[Key Concept: The smallest circle touching two given circles lies on their line of centres.]

Centre will be mid-point of $C_{1}$ and $C_{2}$

$$\equiv \left( \frac{0 + 4}{2},\frac{1 + 9}{2} \right) = (2,5)$$

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