CircleHard
Question
Let the tangents drawn to the circle, x2 + y2 = 16 from the point P(0, h) meet the x-axis at points A and B. If the area of ᐃAPB is minimum, then h is equal to :
Options
A.4√2
B.4√3
C.3√2
D.3√3
Solution
Equation of tangent from (0, h) to the circle is y – h = m (x – 0)
y = mx + h touch the circle
⇒
= 4 ⇒ h = 4
⇒ y = ±
x + h
Area of ᐃ PAB is =
⇒ h = 4√2
y = mx + h touch the circle
⇒
= 4 ⇒ h = 4 ⇒ y = ±x + hArea of ᐃ PAB is =
⇒ h = 4√2
Create a free account to view solution
View Solution FreeMore Circle Questions
The equation of circle passing through the points of intersection of circle x2 + y2 = 6 and x2 + y2 − 6x + 8 = 0 a...If the circles x2 + y2 + 2x − 8y + 8 = 0 and x2 + y2 + 10 x − 2y + 22 = 0 touch each other, their point of c...Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin a...The locus of the mid points of the chords of the circle x2 + y2 - ax - by = 0 which subtend a right angle at is -...Line 3x + 4y = 25 touches the circle x2 + y2 = 25 at the point-...