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Question

Match List-I with List-II

Given $V_{1}$ and $V_{2}$ are initial and final volumes respectively:

List-I (Isothermal process) List-II (Expression)
A. Reversible expansion I. $$q = 0$$
B. Free expansion II. $$q = nRTln\frac{V_{2}}{{\text{ }V}_{1}}$$
C. Irreversible Compression III. $$w = - p_{\text{ext}\text{~}}\left( V_{1} - V_{2} \right)$$
D. Cyclic reversible IV. $$\frac{q_{\text{rev}\text{~}}}{T} = 0$$

Choose the correct answer from the options given below:

Options

A.A-II, B-III, C-I, D-IV
B.A-II, B-I, C-IV, D-III
C.A-II, B-I, C-III, D-IV
D.A-I, B-II, C-III, D-IV

Solution

Sol. [Key Concept: Match each isothermal process to its expression: reversible expansion $q = nRTln\frac{V_{2}}{V_{1}}$, free expansion $q = 0$, irreversible compression $w = - P_{ext}(V_{1} - V_{2})$, cyclic $\frac{q_{rev}}{T} = 0$.]

(A)For isothermal process, $\Delta U = 0$

$W = - nRT\mathcal{l}n\left( \frac{V_{2}}{{\text{ }V}_{1}} \right)$ so $q = nRT\mathcal{l}n\left( \frac{V_{2}}{{\text{ }V}_{1}} \right)$

(B) Free expansion which is isothermal must be adiabatic, so $q = 0$

(C) Irreversible process $W = - P_{\text{ext}\text{~}}\left\lbrack V_{2} - V_{1} \right\rbrack$ $\begin{matrix} & \\ & \end{matrix}\ $

(D) Cyclic process, change in state function (S) so change in entropy must be zero $dS = \frac{{dq}_{rev}}{\text{ }T}$

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