Chemical BondingMedium

Question

Given below are two statements:

Statement I: The number of compounds among ${SO}_{2},{SO}_{3},{SF}_{4},{SF}_{6}$ and $H_{2}\text{ }S$ in which sulphur does not obey the Octet rule is 3 .

Statement II : Among $\left\lbrack H_{2}O,{ClF}_{3},{SF}_{4} \right\rbrack,\left\lbrack {NH}_{3} \right.\ $, $\left. \ {BrF}_{5},{SF}_{4} \right\rbrack,\ \left\lbrack {BrF}_{5},\ {ClF}_{3},\ {XeF}_{4} \right\rbrack\ $ and $\left\lbrack {XeF}_{4} \right.\ $, $\left. \ {ClF}_{3},H_{2}O \right\rbrack$, the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1 .

In the light of the above statements, choose the correct answer from the options given below :

Options

A.Both Statement I and Statement II are true
B.Both Statement I and Statement II are false
C.Statement I is true Statement II is false
D.Statement I is false Statement II is true

Solution

Sol. [Key Concept: Count species where S exceeds the octet (${SO}_{2},{SO}_{3},{SF}_{4},{SF}_{6}$ give $4$, not $3$, so Statement I is false); then find the set with exactly one lone pair on the central atom (Statement II true).]

${SO}_{2},{SO}_{3},{SF}_{6}\&{SF}_{4}$ do not follow octet rule ${NH}_{3},{BrF}_{5},{SF}_{4}$ have one lone pair on central atom ${ClF}_{3},{XeF}_{4}\& H_{2}O$ have two lone pair on central atom.

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