A displacement current of 4.0 A can be set up in the space between two parallel plates of $6\mu ext

Question

A displacement current of 4.0 A can be set up in the space between two parallel plates of $6\mu	ext{ }F$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\alpha 	imes 10^{6}	ext{ }V/s$. The value of $\alpha$ is $\_\_\_\_$ .

Accepted Answer

Sol. [Key Concept: Displacement current $I_{d} = C\frac{dV}{dt}$; solve for $\frac{dV}{dt}$.]$$I_{d} = C\frac{dV}{dt}$$$$\begin{matrix} & 4 = \left( 6 	imes 10^{- 6} ight)\left( \alpha 	imes 10^{6} ight) \ & \alpha = \frac{2}{3} \approx 0.67 \end{matrix}$$

Question

Options

Solution

More Electromagnetic Waves Questions