Errors in measurementMedium
Question
In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and $7^{\text{th}\text{~}}$ Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has
Options
A.0.07 cm negative zero error
B.0.7 cm negative zero error
C.0.07 cm positive zero error
D.0.7 cm positive zero error
Solution
Sol. [Key Concept: Zero error $=$ least count $\times$ coinciding VSD; here LC $= \frac{1}{10}$ mm, and it is positive since zero is shifted to the right.]
Scale reading $=$ main scale + Least count × V.S.R.
$${= 0 + \frac{1}{10} \times 7 = 0.7\text{ }mm }{= 0.07\text{ }cm }$$
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