Atomic StructureMedium
Question
Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.
| A) n = 3 | ℓ = 2 | m = +1 |
|---|---|---|
| B) n = 4 | ℓ = 0 | m = 0 |
| C) n = 6 | ℓ = 1 | m = 0 |
| D) n = 5 | ℓ = 1 | m = +1 |
| E) n = 2 | ℓ = 1 | m = +1 |
Choose the correct answer from the options given below:
Options
A.C < D < B < A < E
B.B < A < E < C < D
C.E < C < D < B < A
D.E < B < A < D < C
Solution
Sol.
| (A) n = 3 | ℓ = 2 | m = +1 ; (n + ℓ) = 5 |
|---|---|---|
| (B) n = 4 | ℓ = 0 | m = 0 ; (n + ℓ) = 4 |
| (C) n = 6 | ℓ = 1 | m = 0 ; (n + ℓ) = 7 |
| (D) n = 5 | ℓ = 1 | m = +1 ; (n + ℓ) = 6 |
| (E) n = 2 | ℓ = 1 | m = +1 ; (n + ℓ) = 3 |
More the value of (n + ℓ), more will be the energy of that particular orbital.
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