Question

Sol. [Key Concept: Count atoms: (A) $2$ mol $C_{6}H_{12} = 2 \times 18$; (B) $684$ g sucrose ($M = 342$) $= 2$ mol$\times 45$; (C) $\frac{90.8}{22.7} = 4$ mol $H_{2} \times 2$; then rank.]

(A) Mole of atoms in $C_{6}H_{12}$

$$\begin{matrix} & \ = 2 \times 18 \\ & \ = 36 \end{matrix}$$

(B) Moles of atoms of sucrose $= \frac{604}{342} \times 45$

(C) $n_{H_{2}} = \frac{90.8}{22.7} = 4$ moles

Mole fo atoms $= 4 \times 2 = 8$

(B) $>$ (A) $>$ (C)