Chemical EquilibriumMedium
Question
The reaction $A(g) \rightleftharpoons B(g) + C(g)$ was initiated with the amount ' a ' of $A(g)$. At equilibrium it is found that the amount of $A(g)$ remaining is $(a - x)$ at a total pressure of p.
The equilibrium constant $K_{p}$ of the reaction can be calculated from the expression :
Options
A.$\frac{x^{2}}{a^{2} + x^{2}} \times p$
B.$\frac{x^{2}}{a^{2} - x^{2}} \times p$
C.$\frac{a + x^{2}}{x^{2}} \times p$
D.$\frac{a - x^{2}}{x^{2}} \times p$
Solution
Sol. [Key Concept: For $A \rightleftharpoons \ B + C$ with amounts $a - x,x,x$ at total pressure $p$, $K_{p} = \frac{x^{2}}{a^{2} - x^{2}} \times \ p$.]
$${\ A(g) \rightleftharpoons B(g) + C(g) }{\begin{matrix} t = 0 & a & 0 & 0 \\ t_{eq} & a - X & X & X \end{matrix} }{K_{p} = \frac{(x)(x)}{(a - x)} \times \left( \frac{P}{a + x} \right) }{K_{P} = \frac{x^{2}P}{a^{2} - x^{2}} }$$
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