Wave OpticsMedium
Question
An unpolarized light of certain intensity passes through a combination of two polarizers whose transmission axes are at $30^{\circ}$ and $90^{\circ}$, respectively, with respect to the horizontal axis. A third polarizer with its transmission axis at $60^{\circ}$ with the horizontal axis is placed between the two existing polarizers. The ratio of the output intensities with and without the third polarizer is $\_\_\_\_$。
Options
A.$3/4$
B.$4/3$
C.$9/4$
D.$4/9$
Solution
Sol. [Key Concept: Apply Malus's law successively through each axis; take the ratio of output intensity with vs. without the third polarizer.]
$$\frac{9I_{0}}{32} \times \frac{8}{I_{0}} = \frac{9}{4}$$
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