From the circuit given below, the capacitance between terminals A and B shown in the circuit is$\_\_

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From the circuit given below, the capacitance between terminals A and B shown in the circuit is$\_\_\_\_$ $\mu F$. (take $C_{1} = C_{2} = C_{3} = 1\mu	ext{ }F$ and $C_{4} = 2\mu	ext{ }F$.)

Accepted Answer

Sol. [Key Concept: Reduce the series $C_{1},C_{2},C_{3}$ with $C_{4}$ across the network to get $C_{AB}$.]$$C_{AB} = 2\mu	ext{ }F $$

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