If x and y coordinates of a projectile as a function of time $(t)$ are given as $24t$ and $43.6t - 4

Question

If x and y coordinates of a projectile as a function of time $(t)$ are given as $24t$ and $43.6t - 4.9t^{2}$, respectively, then the angle (in degrees) made by the projectile with horizontal when $t = 2	ext{ }s$ is $\_\_\_\_$ .

Accepted Answer

Sol. [Key Concept: $tan	heta = \frac{v_{y}}{v_{x}}$ with $v_{x} = 24$ and $v_{y} = 43.6 - 9.8t$, evaluated at $t = 2$ s.]$$x = 24t\ y = 43.6t - 4.9t^{2}$$$$\begin{matrix} & v_{x} = \frac{dx}{dt} = 24 \ & v_{y} = \frac{dy}{dt} = 43.6 - 9.8t \ & tan	heta = \frac{v_{y}}{v_{x}} = \frac{43.6 - 9.8t}{24} \ & Att = 2\frac{43.6 - 19.6}{24} \ & tan	heta = 1 \ & 	heta = 45^{\circ} \end{matrix}$$

Question

Options

Solution

More Kinematics Questions