KinematicsHard
Question
A particle is projected from P(2,0,0) m with a velocity 10m/s making an with the horizontal the plane of projectile motion passes through a horizontal. The coordinates of the point where particle will strike the line PQ is :-
(take g = 10 m/s2)
(take g = 10 m/s2)
Options
A.(10, 6, 0) m
B.(8, 6, 0) m
C.(10, 8, 0) m
D.(6, 10, 0) m
Solution
PQ = R = 
= 10 ⇒ PQ = 10
(x, y) = (10, 6, 0)
= 10 ⇒ PQ = 10 (x, y) = (10, 6, 0) Create a free account to view solution
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