PointMedium
Question
Let the mid points of the sides of a triangle ABC be $\left( \frac{5}{2},7 \right),\left( \frac{5}{2},3 \right)$ and (4, 5). If its incentre is $(h,k)$, then $3\text{ }h + k$ is equal to :
Options
A.11
B.12
C.13
D.14
Solution
Sol. [Key Concept: Recover the vertices from the side-midpoints, then apply the incentre formula.]
$${I = \left( \frac{24}{9},5 \right) }{\therefore 3\text{ }h + k = 8 + 5 = 13 }$$
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