PointHard
Question
The extremities of hypotenuse of a right-angled triangle are (2, 0) and (0, 2), then locus of its third vertex is -
Options
A.x2 + y2 − 2x − 2y = 0
B.x2 + y2 + 2x − 2y = 0
C.x2 + y2 − 2x + 2y = 0
D.x2 + y2 + 2x + 2y = 0
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