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Question

What is the energy (in J atom $\ ^{- 1}$ ) required for the following process?

$${Li}^{2 +}(g) \rightarrow {Li}^{3 +}(g) + e^{-} $$(Take the ionization energy for the H atom in the ground state as $2.18 \times 10^{- 18}{\text{ }J}^{- 1}$ atom $\ ^{- 1}$ )

Options

A.$8.72 \times 10^{- 18}$
B.$1.962 \times 10^{- 18}$
C.$1.962 \times 10^{- 17}$
D.$6.54 \times 10^{- 17}$

Solution

Sol. [Key Concept: Ionization energy $\propto \ Z^{2}$: $E = E_{H} \cdot \ Z^{2}$ with $Z = 3$ for the Li2+-like ion.]

$$E_{{Li}^{2 +}} = E_{H} \times z^{2}$$

$$\begin{matrix} & \ = 2.18 \times 10^{- 18} \times (3)^{2} \\ & \ = 1.962 \times 10^{- 17}\text{ }J{atom}^{- 1} \end{matrix}$$

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