Coordination CompoundHardBloom L3
Question
The number of unpaired electrons calculated in [Co(NH3)6]3+ and [CoF6]3– are :
Options
A.4 and 4
B.0 and 2
C.2 and 4
D.0 and 4
Solution
Sol. [Co(NH3)6]+3 [CoF6]–3
Co+3 = 3d6 Co+3 = 3d6
NH3 is S.F.L. F–is W.F.L.
u.p.e = 0 u.p.e = 4
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