Momentum and CollisionHardBloom L3
Question
Two identical blocks having mass M each are smoothly conjugated and placed on a smooth horizontal floor as shown in figure. On the left of block A there is a wall. A small block of mass m is released from the position. Then velocity of block B is maximum
Options
A.when m is at highest position on B
B.when m is at lowest position and moving towards left w.r.t B
C.when m is at point C
D.is equal to $\frac{m\sqrt{2gh}}{m + M}$
Solution
Sol. When block comes down wedge A, the wedge does not move due to wall.
When block climbs on wedge B, the wedge moves rightward due to normal force between block and wedge B.
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