Momentum and CollisionMediumBloom L3
Question
A particle is projected from a smooth horizontal surface with velocity v at an angle θ from horizontal. Coefficient of restitution between the surface and ball is e. The distance of the point where ball strikes the surface second time from the point of projection is
Options
A.$\frac{v^{2}\sin 2\theta(1 + e^{2})}{g}$
B.$\frac{v^{2}\sin 2\theta(1 + e^{4})}{g}$
C.$\frac{v^{2}\sin 2\theta(1 + e^{3})}{g}$
D.$\frac{v^{2}\sin 2\theta(1 + e)}{g}$
Solution
Sol. 
R = R1 + R2
= Vcosθ
+ Vcosθ 
= $\frac{V^{2}\sin 2\theta(1 + e)}{g}$
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