Momentum and CollisionMediumBloom L3
Question
A ball strikes a smooth horizontal ground at an angle of 45° with the vertical. What cannot be the possible angle of its velocity with the vertical after the collision. (Assume e ≤ 1).
Options
A.45°
B.30°
C.53°
D.60°
Solution
Sol.
tanθ = $\frac{v_{0}}{ev_{0}} = \frac{1}{e}$ e ≤1
tanθ ≥ 1 ⇒ θ ≥ 45°
∴ Ans. (B)
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