Momentum and CollisionHard

Question

Object A strikes stationary object B with given speed u head-on in an elastic collision. The mass of A is fixed; you may only choose the mass of B appropriately for following cases. Then after collision:

Options

A.For B to have the greater speed, choose mB = mA
B.For B to have the greater momentum, choose  mB << mA
C.For B to have the greater speed choose  mB << mA
D.For the maximum fraction of kinetic energy transfer, choose mB = mA

Solution

mAu = mAuA + mBvB and e = 1 = ⇒ vB =
For mA >> mB , vB = 2u
For mA = mB, vB = u
For mA << mB, vB = 0
kinetic energy KB = mBvB2 =

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