Circular MotionMediumBloom L3
Question
A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\overrightarrow{a} = \left( 4\widehat{i} + 3\widehat{j} \right)$ m/s2 and $\overrightarrow{p} = \left( 8\widehat{i} - 6\widehat{j} \right)$ kg–m/s. The motion of the particle is
Options
A.uniform circular motion
B.accelerated circular motion
C.de–accelerated circular motion
D.we can not say anything with $\overrightarrow{a}$ and $\overrightarrow{p}$ only
Solution
Sol. $\frac{\overrightarrow{a}.\overrightarrow{p}}{\left| \overrightarrow{a} \right|\left| \overrightarrow{p} \right|} = \cos\theta$
⇒ 0 < q < 90°
⇒ accelerated circular motion
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