Circular MotionMedium
Question
In the above question, 
. is non-negative at the lowest point for:
. is non-negative at the lowest point for:Options
A.u ≤ 
B.u =
C.u <
D.any value of u
Solution
= | T | | a | cos θθ = 0o at lowest point
So
= | T | | a | ≥ 0 for every value of uCreate a free account to view solution
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