The magnitudes of power of a biconvex lens (refractive index 1.5) and that of a plano-concave lens (

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The magnitudes of power of a biconvex lens (refractive index 1.5) and that of a plano-concave lens (refractive index $= 1.7$ ) are same. If the curvature of plano-concave lens exactly matches with the curvature of back surface of the biconvex lens, then ratio of radius of curvature of front and back surface of the biconvex lens is $\_\_\_\_$。

Accepted Answer

$${\left| P_{A} \right| = \left| P_{B} \right| }{0.5\left( \frac{1}{R_{1}} + \frac{1}{R_{2}} \right) = \frac{0.7}{R_{2}} }{\frac{5}{R_{1}} = \frac{2}{R_{2}} }{\frac{R_{1}}{R_{2}} = \frac{5}{2}}$$

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