$20.0{dm}^{3}$ of an ideal gas ' X ' at 600 K and 0.5 MPa undergoes isothermal reversible expansion

Question

$20.0{dm}^{3}$ of an ideal gas ' X ' at 600 K and 0.5 MPa undergoes isothermal reversible expansion until pressure of the gas is 0.2 MPa . Which of the following option is correct?

(Given: $log2 = 0.3010$ and $log5 = 0.6989$ )

Accepted Answer

For isothermal reversible process $\Delta U = \Delta H = 0$

$${w_{\text{iso~}} = - p_{1}v_{1}ln\frac{P_{1}}{P_{2}} }{w_{\text{iso~}} = - 0.5 \times 10^{6} \times 20 \times 10^{- 3}ln\frac{0.5}{0.2} }{w_{\text{iso~}} = - 0.5 \times 10^{6} \times 20 \times 10^{- 3} \times 2.303 \times (.6989 - .3010) }{w \simeq - 9.1\text{ }kJ }{q = - w = 9.1\text{ }kJ}$$

Question

Options

Solution

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