ThermodynamicsHard
Question
A thermally insulated vessel containing a gas whose molar mass is equal to 40 and ratio of specific heats is 1.5, moves with a velocity 100 m/s. Find the gas temperature increment (in oC) resulting from the sudden stoppage of the vessel.
Options
A.12
B.24
C.36
D.48
Solution
$K.E. = \Delta U \Rightarrow \frac{1}{2} \times \frac{(n \times 40)}{1000} \times (100)^{2} = n \times \frac{8.314}{(1.5 - 1)} \times \Delta T$
$\therefore\Delta T = 12.30\text{ K}$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Five moles of an ideal gas expand isothermally and reversibly from an initial pressure of 100 atm to a final pressure of...Standard entropies of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For the reaction y2 ⇋ XY3 ; ᐃ...one mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27oC. if the work done ...The direct conversion of A to B is difficult, hence it is carried out by the following shown path: Given ᐃS(A U...The magnitude of work done by one mole of a Van der Waals gas during its isothermal reversible expansion from volume V1 ...