Nuclear Physics and RadioactivityHard
Question
The binding energy for the following nuclear reactions are expressed in MeV .
$$\begin{matrix} & \ _{2}{He}^{3} + \ _{0}n^{1} \rightarrow \ _{2}{He}^{4} + 20MeV \\ & \ _{2}{He}^{4} + \ _{0}n^{1} \rightarrow \ _{2}{He}^{5} - 0.9MeV \end{matrix}$$
If $X_{3},X_{4},X_{5}$ denote the stability of $\ _{2}{He}^{3},\ _{2}{He}^{4}$ and $\ _{2}{He}^{5}$, respectively, then the correct order is :
Options
A.$X_{4} > X_{5} > X_{3}$
B.$X_{4} = X_{5} = X_{3}$
C.$X_{4} > X_{5} < X_{3}$
D.$X_{4} < X_{5} < X_{3}$
Solution
${BE}_{{He}^{4}} - {BE}_{{He}^{3}} = 20MeV$
$$\begin{array}{r} {BE}_{{He}^{5}} - {BE}_{{He}^{4}} = - 0.9MeV\#(1) \end{array}$$
From eq (1) & (2)
$$\begin{matrix} & {BE}_{{He}^{4}} > {BE}_{{He}^{5}} > {BE}_{{He}^{3}} \\ & X_{4} > X_{5} > X_{3} \end{matrix}$$
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