Nuclear Physics and RadioactivityHard

Question

In the fusion reaction 21H + 21HH → 32He + 10n, the masses of deuteron, helium and neutron expressed in amu are 2.015, 3.017 and 1.009 respectively. If 1 kg of deuterium undergoes complete fusion, find the amount of total energy released (Take : 1 amu = 931.5 MeV/c2)

Options

A.≈ 6.02 × 1013J
B.≈ 5.6 × 1013J
C.≈ 9.6 × 1013J
D.≈ 0.6 × 1013J

Solution

E = ᐃmc2
= ᐃmamu × 931.5 MeV

Create a free account to view solution

View Solution Free
Topic: Nuclear Physics and Radioactivity·Practice all Nuclear Physics and Radioactivity questions

More Nuclear Physics and Radioactivity Questions