Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure

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Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure A and B are 55 and $15{kNm}^{- 2}$ respectively. What is the mole fraction of A in solution of A and $B$ in equilibrium with a vapour in which the mole fraction of A is 0.8 ?

Accepted Answer

$\frac{Y_{A}}{Y_{B}} = \frac{P_{A}^{o}}{P_{B}^{0}} \cdot \frac{X_{A}}{X_{B}}$

$${\frac{0.8}{0.2} = \frac{55}{15} \times \frac{X_{A}}{X_{B}} }{\frac{X_{A}}{X_{B}} = \frac{60}{55} = \frac{12}{11} }{X_{A} = \frac{12}{23} = 0.5217}$$

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