SHMMedium
Question
A spring of force constant $15\text{ }N/m$ is cut into two pieces. If the ratio of their length is $1:3$, then the force constant of smaller piece is $\_\_\_\_$ $N/m$
Options
A.15
B.20
C.60
D.45
Solution
$K\mathcal{l} =$ constant
$${K\mathcal{l} = K'\left( \frac{\mathcal{l}}{4} \right) }{K' = 4\text{ }K }{K' = 60\text{ }N/m}$$
Create a free account to view solution
View Solution FreeMore SHM Questions
A horizontal platform with an object placed on it is executing simple harmonic motion in the vertical direction. The amp...x and y displacements of a particle are given as x(t) = a sin ωt and y(t) = a sin 2ωt. Its trajectory will loo...A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec . the time required by it to...In the above question, the value of phase constant will be :...The time period of oscillation of a mass m suspended from a spring is 2 seconds. If another 2 kg mass is also suspended ...