Work, Power and EnergyHard
Question
A spring of force constant $15\text{ }N/m$ is cut into two pieces. If the ratio of their length is $1:3$, then the force constant of smaller piece is $\_\_\_\_$ $N/m$
Options
A.15
B.20
C.60
D.45
Solution
$K\mathcal{l} =$ constant
$${K\mathcal{l} = K'\left( \frac{\mathcal{l}}{4} \right) }{K' = 4\text{ }K }{K' = 60\text{ }N/m}$$
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