JEE Advanced | 2015Work, Power and EnergyHard
Question
An ideal monoatomic gas is confined in a horizontal cylinder by a spring loaded piston (as shown
in the figure). Initially the gas is at temperature T1, pressure P1 and volume V1 and the spring is in
its relaxed state. The gas is then heated very slowly to temperature T2, pressure P2 and volume V2.
During this process the piston moves out by a distance x. Ignoring the friction between the piston
and the cylinder, the correct statement(s) is(are) :-
in the figure). Initially the gas is at temperature T1, pressure P1 and volume V1 and the spring is in
its relaxed state. The gas is then heated very slowly to temperature T2, pressure P2 and volume V2.
During this process the piston moves out by a distance x. Ignoring the friction between the piston
and the cylinder, the correct statement(s) is(are) :-
Options
A.If V2 = 2V1 and T2 = 3T1, then the energy stored in the spring is 1/4 P1V1
B.If V2 = 2V1 and T2 = 3T1, then the change in internal energy is 3 P1V1
C.If V2 = 3V1 and T2 = 4T1, then the work done by the gas is 7/3 P1V1
D.If V2 = 3V1 and T2 = 4T1, then the heat supplied to the gas is 17/6 P1V1
Solution
if V2 = 2V1 & T2 = 3T1
⇒ P2 =
P1ᐃU = f/2 (nRᐃT) =
(P2V2 - P1V1)=
× 2P1V1 = 3P1V1Create a free account to view solution
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