Basic Maths and Units and DimensionsMedium
Question
Match the List-I with List-II
| List-I | List-II | ||
|---|---|---|---|
| A. | Magnetic induction | I. | $$MLT^{- 2}{\text{ }A}^{- 2}$$ |
| B. | Magnetic flux | II. | $$ML^{2}{\text{ }T}^{- 2}{\text{ }A}^{- 2}$$ |
| C. | Magnetic permeability | III. | $$ML^{0}{\text{ }T}^{- 2}{\text{ }A}^{- 1}$$ |
| D. | Self inductance | IV. | $$ML^{2}{\text{ }T}^{- 2}{\text{ }A}^{- 1}$$ |
Choose the correct answer from the options given below:
Options
A.A-IV,B-III,C-I,D-II
B.A-III,B-IV,C-II,D-I
C.A-I,B-III,C-IV,D-II
D.A-III,B-IV,C-I,D-II
Solution
Magnetic induction
$${F = qvB }{\lbrack B\rbrack = \left\lbrack \frac{F}{qV} \right\rbrack }{\lbrack B\rbrack = \left\lbrack {MT}^{- 2}{\text{ }A}^{- 1} \right\rbrack }$$Magnetic Flux ( $\phi$ )
$\phi = (B)$. (Area)
$$\lbrack\phi\rbrack = \left\lbrack {ML}^{2}{\text{ }T}^{- 2}{\text{ }A}^{- 1} \right\rbrack $$Magnetic Permeability
$$\lbrack\mu\rbrack = \left\lbrack {MLT}^{- 2}{\text{ }A}^{- 2} \right\rbrack $$Self inductance
Using $U = \frac{1}{2}{LI}^{2}$
[Self inductance] $= \left\lbrack {ML}^{2}{\text{ }T}^{- 2}{\text{ }A}^{- 1} \right\rbrack$
A - III, B - IV, C - I, D – II
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