ElectroMagnetic InductionHard
Question
The figure shows a rod of length l with points A and B on it. The rod is moved in a uniform magnetic field (B0) in different ways as shown. In which case potential difference (VA - VB) between A & B is minimum?
Options
A.

B.

C.

D.

Solution
For (A) : VB - VA =
Bωl2 ⇒ VA - VB = -
Bωl2
For (B) : VB - VA = Bvl = B
l =
Bωl2 ⇒ VA - VB = -
Bωl2
For (C) : VA - VB = 0
For (D) : VB - VA =
Bωl2 -
Bω
=
Bωl2 ⇒ VA - VB = -
Bωl2
For (B) : VB - VA = Bvl = B
For (C) : VA - VB = 0
For (D) : VB - VA =
Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
In a series L − R growth circuit, if maximum current and maximum induced emf in an inductor of inductance 3mH are ...The self inductance of the motor of an electric fan is 10 H. In order to impart maximum power at 50 Hz, it should be con...A transformer is used to :-...PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with co...In an LR circuit current at t = 0 is 20 A. After 2s it reduces to 18 A. The time constant of the circuit is (in second):...