Set, Relation and FunctionHard
Question
Let R be a relation defined on the set $\{ 1,2,3,4\} \times \{ 1,2,3,4\}$ by
$R = \{((a,b),(c,d)):2a + 3\text{ }b = 3c + 4\text{ }d\}$.
Then the number of elements in R is
Options
A.6
B.18
C.12
D.15
Solution
| Sol. (a,b) | (c,d) | |
|---|---|---|
| (1, 1) | x | |
| $$(1,2)$$ | x | |
| $$(1,3)$$ | $$(1,2)$$ | |
| $$(1,4)$$ | $$(2,2)$$ | |
| $$(2,1)$$ | $$(1,1)$$ | |
| $$(2,2)$$ | $$(2,1)$$ | |
| $$(2,3)$$ | $$(3,1)$$ | |
| $$(2,4)$$ | $$(4,1)$$ | |
| $$(3,1)$$ | x | |
| $$(3,2)$$ | x | |
| $$(3,3)$$ | $$(1,3)$$ | |
| $$(3,4)$$ | $$(2,3)$$ | |
| $$(4,1)$$ | $$(1,2)$$ | |
| $$(4,2)$$ | $$(2,2)$$ | |
| $$(4,3)$$ | $$(3,2)$$ | |
| $$(4,4)$$ | $$(4,2)$$ |
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